Hi,

 When I mouseover an asp:linkbutton on my webpage some code shows up in the status bar, bottom left hand corner of i.e saying javascript:webform_....true..false etc, all I want to do here is display the page this link will navigate to. Is there a way this can be achieved?

Thanks, Jonathan 

Try this:

I don't know how an asp:linkbutton will render in HTML (an anchor maybe?), but I'm pretty sure whatever it renders supports javascript's onmouseover, onmouseout functions.

<asp:linkButton onmouseover="window.status='your message';" onmouseout="window.status=''";/>

Thanks for your reply. Its nearly there once I 'mouseout' I get my message but unfortunately one mouseover I still get all the javascript code etc.

<li><asp:LinkButton onmouseover="window.status='TEST'" onmouseout="window.status=''" ID="property" PostBackUrl="~/Default.aspx" CausesValidation="false" runat="server"><b>Property</b></asp:LinkButton></li>

Hi,

jonnyjc273:

but unfortunately one mouseover I still get all the javascript code etc.

You should append the code: return true at the onmouseover event, but this will make the satus always dispay, so you also need to set the status is empty in the onmouseout event

You can try to refer below code:

1. the aspx code:

<asp:LinkButton ID="LinkButton1" runat="server" PostBackUrl="http://ww.126.com" onmouseout="window.defaultStatus =''" >LinkButton</asp:LinkButton>
         <script type="text/javascript">
    function abc(url)
    {      
        window.setTimeout('window.defaultStatus =\''+url+"\'",10);
    }
   

2. the codebehind:

 protected void Page_Load(object sender, EventArgs e)
    {
        this.LinkButton1.Attributes.Add("onmouseover", "abc('"+LinkButton1.PostBackUrl+"');return true;");
    }

Hope it helps.